Picture the scene. It’s a chilly November night and you’re standing outside in the dark. Beside you, a crackling bonfire greedily works its way through old pallets and branches. A few jagged nails stick out of the half-rotten wood, tinged dull orange-brown with flaking rust. Believe it or not, the burning wood and rusting metal have something in common - they’re both examples of redox reactions.
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Jetzt kostenlos anmeldenPicture the scene. It’s a chilly November night and you’re standing outside in the dark. Beside you, a crackling bonfire greedily works its way through old pallets and branches. A few jagged nails stick out of the half-rotten wood, tinged dull orange-brown with flaking rust. Believe it or not, the burning wood and rusting metal have something in common - they’re both examples of redox reactions.
Redox is a term used to describe reactions involving both oxidation and reduction. These reactions involve a movement of electrons, and are characterised by a change in oxidation states.
The term redox is short for reduction-oxidation, and is used to describe reactions involving - you guessed it - both oxidation reactions and reduction reactions. Redox reactions all feature a movement of electrons and a change in oxidation state.
Let’s look more closely at the definitions of oxidation and reduction.
The words oxidation and reduction have a few different meanings in chemistry. The first definition looks at them in terms of oxygen. Take a punt - you can probably guess what oxidation means.
Oxidation is the gain of oxygen.
You can think of reduction as the opposite of oxidation.
Reduction is the loss of oxygen.
For example, when copper reacts with oxygen, it forms copper oxide. The copper is oxidised.
Cu(s) + ½ O2(g) → CuO(s)
But reacting hydrogen with copper oxide separates the copper and the oxygen. The copper oxide is reduced.
CuO(s) + H2(g) → Cu(s) + H2O(l)
Did you notice that we added hydrogen to reduce copper oxide? This leads us to the second set of definitions for oxidation and reduction.
Oxidation is the loss of hydrogen, and reduction is the gain of hydrogen.
However, in chemistry, we tend to use a different definition. It refers to the movement of electrons between species in a reaction, and it is the definition we'll focus on for the rest of this topic.
Oxidation is the loss of electrons, and reduction is the gain of electrons.
There’s a handy acronym that will help you remember this third definition: OILRIG.
Let’s revisit the example from before. What happens when copper reacts with oxygen? It forms copper oxide, an ionic compound. Copper oxide is made up of copper ions and oxygen ions, Cu2+ and O2- respectively. To form these ions from neutral atoms, we need to move some electrons around.
Because both oxidation and reduction are happening side by side, this is an example of a redox reaction.
In summary, oxidation can mean:
Likewise, reduction can mean:
We know what oxidation and reduction reactions are. Now let’s look at the species that carry out these reactions.
Oxidising agents are species that oxidise another atom, ion, or compound. They are reduced in the process.
Oxidising agents take electrons from another species - they oxidise it. They are also called oxidants. Some particularly strong oxidising agents are fluorine and, perhaps unsurprisingly, oxygen.
There are several factors that affect the strength of an oxidising agent. These include electronegativity, electron affinity enthalpy, and oxidation state, which we’ll look at in just a second. This is because oxidising agents take electrons, so anything that increases the attraction between an atom or ion and an incoming electron will increase the agent’s oxidising strength. For example, fluorine is the most electronegative element in the periodic table, which makes it a very strong oxidising agent. Species with a high oxidation state also tend to be good oxidising agents.
We now know what oxidising agents are. What do you think reducing agents are? You can probably take a good guess.
Reducing agents are species that reduce another atom, ion, or compound. They are oxidised in the process.
Reducing agents donate electrons to another species - they reduce it. They are also called reductants. Many metals, such as lithium, aluminium, and zinc, are good reducing agents, and so is hydrogen gas (if it is in the presence of a nickel catalyst).
Once again, there is a handy acronym that will help you remember the actions of oxidising and reducing agents in terms of electrons: RAD OAT.
Take the example of copper and oxygen again. We know that copper is oxidised and oxygen is reduced. Copper loses two electrons, which oxygen gains. This also means that copper acts as a reducing agent and oxygen acts as an oxidising agent.
You should now feel confident about the terms oxidation, reduction, oxidising agent, and reducing agent. Let's move on to our next topic.
Now that we know what redox reactions are, we can look at how to work out which species is oxidised and which species is reduced in a reaction. To do this, we use oxidation states.
Oxidation states are numbers assigned to ions that show how many electrons the ion has lost or gained, compared to the element in its uncombined state. A positive oxidation state shows that the element lost electrons, whilst a negative oxidation state shows that it gained electrons. They can also be referred to as oxidation numbers.
We can use changes in oxidation states to see whether species have been oxidised or reduced. Going from a positive oxidation state to a more negative oxidation state means that the species has gained electrons. It has therefore been reduced. On the other hand, going from a negative oxidation state to a more positive oxidation state means that the species has lost electrons. It has therefore been oxidised.
It is all well and good knowing what an oxidation state is, but how do you assign them? There are a few rules you can use to find out a species' oxidation state.
We can use this knowledge to calculate oxidation states of unknown elements in compounds and ions. Here's an example:
What is the oxidation state of copper in copper oxide, CuO?
To solve this problem, look at the copper ions in copper oxide. They are ions with a charge of 2+. How do you turn an uncombined atom, which is just a neutral atom on its own, into an ion with a charge of 2+? By losing two electrons! To form a copper ion with a charge of 2+, each copper atom has to lose two electrons. This means that these copper ions have an oxidation state of +2.
When talking about charges, we put the number first: 2+. But when talking about oxidation states, we put the positive or negative symbol first: +2.
If you want to see further examples of oxidation states in action, head over to "Oxidation Number" for more worked problems.
Although some elements only form ions with one oxidation state, some elements can form ions with multiple different oxidation states. To avoid confusion when talking about these ions, we show oxidation states using roman numerals.
For example, when talking about the copper ions in CuO with an oxidation state of +2, we would write copper(II).
A redox equation is a way of representing a redox reaction.
During a redox reaction, two simultaneous processes occur - reduction and oxidation. We can show these processes using one overall equation that ignores any ions that aren’t oxidised or reduced - that is to say, aren't taking part in the reaction. These are known as spectator ions.
Spectator ions are ions that are present in both the reactants and products of a reaction. They are totally unchanged by the reaction - their physical state, oxidation state, and charge don’t change.
We'll now focus on how you can write redox equations, using some worked examples. Here’s one such example: the displacement reaction between magnesium and copper sulfate.
Write a redox equation for the reaction between magnesium and copper sulfate. The overall equation is given below:
Mg(s) + CuSO4(aq) → MgSO4(aq) + Cu(s)
First of all, we need to find out the spectator ions in the equation. These don't change oxidation states. They aren't oxidised or reduced, so we don't need to worry about them.
To help you identify the spectator ions, split the ionic salts into their constituent ions:
Mg(s) + Cu2+(aq) + SO42-(aq) → Mg2+(aq) + SO42-(aq) + Cu(s)
The sulfate ion, SO42-, is present on both sides of the equation. It doesn’t change physical state, oxidation state, or charge. This means that it is a spectator ion. To write an overall redox equation, we simply omit this ion. Here's your final answer:
Mg(s) + Cu2+(aq) → Mg2+(aq) + Cu(s)
Redox equations are useful for showing an overall redox reaction. One species is oxidised whilst another is reduced, meaning that there is an overall movement of electrons. However, they can make it tricky to identify the individual oxidation and reduction processes. To see those more clearly, we often use half equations.
Half equations are equations that show one half of a redox reaction. One half equation shows the oxidation process, whilst the other shows the reduction process.
To write half equations, we consider each of the ions or atoms involved in the redox equation separately. We add in electrons to show the processes of oxidation and reduction, and might also have to add in water or hydrogen ions to balance the equation.
These steps should help you learn how to write half equations.
The only three things you can add into half equations, besides more of the reactant or product, are water, hydrogen ions, and electrons. You can't sneak in oxygen gas, for example.
This process may sound a little tricky, but don't worry - we've got lots of examples over at "Half Equations" to get you started.
Let’s now touch on disproportionation reactions. Before, we only looked at equations where a species was either oxidised or reduced. In disproportionation reactions, both processes occur.
Disproportionation reactions are reactions where the same species is both oxidised and reduced.
We can see whether a species has been reduced, oxidised, or both by looking at its oxidation states. Here’s an example:
We can see the following:
Because copper has been both oxidised and reduced, this is a disproportionation reaction. This is just one example of a type of redox reaction. Let’s now look at some more.
There are a few common examples of redox reactions. One of these includes electrolysis.
Electrolysis is a way of splitting ionic compounds into simpler substances by passing an electrical current through them. Either reduction or oxidation takes place at the system's two electrodes:
For example, electrolysis of sodium chloride produces chlorine gas at the anode and hydrogen gas at the cathode. Chloride ions are oxidised whilst hydrogen ions are reduced.
2Cl- → Cl2 + 2e-
2H+ + 2e- → H2
Further examples of redox reactions in everyday life are rusting, respiration, and combustion.
We can identify redox reactions because they cause the oxidation state(s) of one or more species to change.
A redox reaction is a reaction involving both oxidation and reduction.
A simple redox reaction is a displacement reaction between two metals, such as adding magnesium to a solution of Fe2+ ions. The magnesium is oxidised and loses electrons, whilst the iron is reduced and gains these electrons. Examples of more complicated redox reactions include respiration, combustion, and rusting.
In electrolysis, reduction and oxidation both happen simultaneously. This makes it an example of a redox reaction. At the cathode, positive cations gain electrons and so are reduced, whilst at the anode, negative anions lose electrons and so are oxidised.
In redox reactions, one species is oxidised and another species is reduced. The oxidised species loses electrons, while the reduced species gains these electrons.
What is a redox reaction?
A reaction involving both oxidation and reduction.
Which of the following are definitions of oxidation?
Gain of oxygen
Which of the following are definitions of reduction?
Gain of hydrogen
Which of the following are redox reactions?
Mg + Cu2+ → Mg2+ + Cu
What does the acronym OIL RIG stand for?
Oxidation is loss, reduction is gain.
What does the acronym RAD OAT stand for?
Reducing agents donate, oxidising agents take.
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